Community USForum Map - Rev #334

[Hellpotatoe]

I want the top a little above the equator

[FiahOwl]

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[atomic7732]

Nice weather disruptors you have there. Have fun with your wacky eddies and rain shadows and stuff.

[FiahOwl]

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[atomic7732]

Electric disturbances. I have no idea what that'd do to the atmosphere downwind. This is in addition to the eddies and rain shadows.

[vh]

yes well whenever i want weather disturbances i throw 50 ton spheres of aerogel.

[atomic7732]

Basin defining borders for the eastern hemisphere 30E to 135E.

The longitudinal lines should be correct, but the lateral ones are messed up due to the curvature of Earth (the main reason Mercator is a legitimate projection: the shortest path from one point to another point on the same latitude is NOT the latitude line connecting them)

In any case, as defined for all RSMCs defined by the Nausikkak Meteorological Collaboration, regional responsibility extends north so long as there is no other RSMC responsible for the region north of the subject region. Regions also extend inland regardless of regional responsibility, especially in cases where the affected nation is involved outside of it's area of responsibility.

There are definitely plans for the dissolution of most Akolenal Sea AORs.

[Darvince]

no there are not

[atomic7732]

well in Auspikitan there are and they will probably bring it up every annual meeting of the NMC. Also the plan does not involve the dissolution of any national responsibility at all, only official cyclone tracking would go to one or two nations.

Also does every nation use different scales because if so I can just imagine the extreme impossibility of tracking that basin.

[FiahOwl]

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[Hellpotatoe]

Iz-Lato is naw Ezheatio

[vh]

the average ns regional map (selected completely randomly)

http://i1114.photobucket.com/albums/k525/metspelf34/UrceaMapIxnaycopy.png
http://i.imgur.com/l9ph7.png
http://imageshack.us/a/img838/1765/tychromemap.jpg
http://i.imgur.com/djXAC.jpg
http://i1234.photobucket.com/albums/ff407/allyboy2/TheCommonwealthofKings_zps84b8db87.png
http://i.imgur.com/cllI8.png
http://i1116.photobucket.com/albums/k570/greatkingston/NS%20Stuff/NatalPoliticalMap.png

and these are probably the better ones; they came up in search first

[vh]

also i think we should consider angular resolution important. currently the angular resolution for most parts of nausikakk are about 0.008 radians, (east nueland is more like 0.02 radians).
kallisto is about 0.008 radians
potatoeland is also about 0.02 radians and fiahland varies between 0.007 and 0.012 radians.
artic fiahland is about 0.004 radians and artic neutraland is about 0.016 radians.

i think we should make the standard from 0.005 to 0.01 radians, preferably 0.008 radians, no more and no less, so that the mapp doesn't look like a clash of high and low resolution merges, which it is atm

i'll put up a poll later

[FiahOwl]

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[vh]

angular resolution is the smallest area you can tell.


top is low angular resolution
bottom is high angular resolution
now if we mixed those too together it'd look pretty ugly.

to determine angular resolution on an equirectangular map, you can do this:
select a random point on a border
make an imaginary circle around it, and pretend you can't see anything outside of it
slowly expand circle from 0 pixels radius to A pixels radius.
you stop expanding the circle when you can tell that the line is turning/is not just a straight line
2A is the amount of pixels

since 2A pixels is just an arc on a sphere/circle, you need to find the circumference. At the equator, the circumferemce is 4096, and at the poles, the circumference is 0. there is an equation that can tell you how many pixels the circumference has

2A/4096 or 2A/1293 or however many pixels

multiply that by 2*pi to convert from percent to angle

there you go, angular resolution.

[vh]

oh this is the equation

C=4*sqrt(1048576-d^2)
where d is the distance from the equator, C is the circumference of the circle

all units in pixels

[Darvince]

how much is himalia

[vh]

0.008 radians

[vh]

also i think we should consider angular resolution important. currently the angular resolution for most parts of nausikakk are about 0.008 radians, (east nueland is more like 0.02 radians).
kallisto is about 0.008 radians
potatoeland is also about 0.02 radians and fiahland varies between 0.007 and 0.012 radians.
artic fiahland is about 0.004 radians and artic neutraland is about 0.016 radians.

i think we should make the standard from 0.005 to 0.01 radians, preferably 0.008 radians, no more and no less, so that the mapp doesn't look like a clash of high and low resolution merges, which it is atm

i'll put up a poll later

angular resolution is the smallest area you can tell.


top is low angular resolution
bottom is high angular resolution
now if we mixed those too together it'd look pretty ugly.

to determine angular resolution on an equirectangular map, you can do this:
select a random point on a border
make an imaginary circle around it, and pretend you can't see anything outside of it
slowly expand circle from 0 pixels radius to A pixels radius.
you stop expanding the circle when you can tell that the line is turning/is not just a straight line
2A is the amount of pixels

since 2A pixels is just an arc on a sphere/circle, you need to find the circumference. At the equator, the circumferemce is 4096, and at the poles, the circumference is 0. there is an equation that can tell you how many pixels the circumference has

2A/4096 or 2A/1293 or however many pixels

multiply that by 2*pi to convert from percent to angle

there you go, angular resolution.

https://docs.google.com/spreadsheet/ccc?key=0AqXNpALRcpv9dFJxQnphMGNKWUpFQ0xBUWg0YVFJLUE#gid=0

at the bottom of list.

[FiahOwl]

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[vh]

-snip-

swonx could i move aiota to the east a bit so that it's nearer hellpotatoe's land, then i can attach an isthmus to and create a continent.

[Hellpotatoe]

-snip-

swonx could i move aiota to the east a bit so that it's nearer hellpotatoe's land, then i can attach an isthmus to and create a continent.

No, because thats not ma official nashuns

[Hellpotatoe]

Fixin'


Edit-Fixed
Edit2- Fixed Again''

[Hellpotatoe]

https://docs.google.com/spreadsheet/ccc?key=0AqXNpALRcpv9dFJxQnphMGNKWUpFQ0xBUWg0YVFJLUE#gid=0

at the bottom of list.

Layers format
I vote: paint.net

angular resolution
minumum limit:
I vote: 0.07

maximum limit:
I vote: 0.1

[vh]

KOLOK added

[FiahOwl]

This message is only viewable with Universe Sandbox Galaxy Edition. Access it and much more with promo-code '86110'.

[FiahOwl]

This message is only viewable with Universe Sandbox Galaxy Edition. Access it and much more with promo-code '86112'.

[vh]

also i think we should consider angular resolution important. currently the angular resolution for most parts of nausikakk are about 0.008 radians, (east nueland is more like 0.02 radians).
kallisto is about 0.008 radians
potatoeland is also about 0.02 radians and fiahland varies between 0.007 and 0.012 radians.
artic fiahland is about 0.004 radians and artic neutraland is about 0.016 radians.

i think we should make the standard from 0.005 to 0.01 radians, preferably 0.008 radians, no more and no less, so that the mapp doesn't look like a clash of high and low resolution merges, which it is atm

i'll put up a poll later

angular resolution is the smallest area you can tell.


top is low angular resolution
bottom is high angular resolution
now if we mixed those too together it'd look pretty ugly.

to determine angular resolution on an equirectangular map, you can do this:
select a random point on a border
make an imaginary circle around it, and pretend you can't see anything outside of it
slowly expand circle from 0 pixels radius to A pixels radius.
you stop expanding the circle when you can tell that the line is turning/is not just a straight line
2A is the amount of pixels

since 2A pixels is just an arc on a sphere/circle, you need to find the circumference. At the equator, the circumferemce is 4096, and at the poles, the circumference is 0. there is an equation that can tell you how many pixels the circumference has

2A/4096 or 2A/1293 or however many pixels

multiply that by 2*pi to convert from percent to angle

there you go, angular resolution.

https://docs.google.com/spreadsheet/ccc?key=0AqXNpALRcpv9dFJxQnphMGNKWUpFQ0xBUWg0YVFJLUE#gid=0

at the bottom of list.

[vh]

people you must use the gimp file


fiahowl can i or you turn that ugly half-island in south aeridani into an island with nonstraight sides since it doesn't look like it will be completed

hellpotatoe can i shrink your land which is currently about the size of sagualand, darvincia, and ska combined

swonx can i move your island a bit to the east.

[vh]

also i think we should consider angular resolution important. currently the angular resolution for most parts of nausikakk are about 0.008 radians, (east nueland is more like 0.02 radians).
kallisto is about 0.008 radians
potatoeland is also about 0.02 radians and fiahland varies between 0.007 and 0.012 radians.
artic fiahland is about 0.004 radians and artic neutraland is about 0.016 radians.

i think we should make the standard from 0.005 to 0.01 radians, preferably 0.008 radians, no more and no less, so that the mapp doesn't look like a clash of high and low resolution merges, which it is atm

i'll put up a poll later

angular resolution is the smallest area you can tell.


top is low angular resolution
bottom is high angular resolution
now if we mixed those too together it'd look pretty ugly.

to determine angular resolution on an equirectangular map, you can do this:
select a random point on a border
make an imaginary circle around it, and pretend you can't see anything outside of it
slowly expand circle from 0 pixels radius to A pixels radius.
you stop expanding the circle when you can tell that the line is turning/is not just a straight line
2A is the amount of pixels

since 2A pixels is just an arc on a sphere/circle, you need to find the circumference. At the equator, the circumferemce is 4096, and at the poles, the circumference is 0. there is an equation that can tell you how many pixels the circumference has

2A/4096 or 2A/1293 or however many pixels

multiply that by 2*pi to convert from percent to angle

there you go, angular resolution.

https://docs.google.com/spreadsheet/ccc?key=0AqXNpALRcpv9dFJxQnphMGNKWUpFQ0xBUWg0YVFJLUE#gid=0

at the bottom of list.