Author Topic: What should Universe Sandbox 2 cost? (Read 50617 times)

deoxy99 · « **Reply #30 on:** March 07, 2010, 05:19:21 PM »

I think 15 is enough!

You know it is a good price, just look into your mind.

deoxy99 · « **Reply #31 on:** March 07, 2010, 07:35:22 PM »

50 for Academic
25 for the others

That is what you meant to say.

Chaotic Cow · « **Reply #32 on:** March 07, 2010, 08:16:23 PM »

Quote from: deoxy99 on March 07, 2010, 07:35:22 PM

50 for Academic
25 for the others

That is what you meant to say.

This makes sense.

witold · « **Reply #33 on:** March 08, 2010, 10:18:28 AM »

FREE FOR EVERYONE!!!

Bla · « **Reply #34 on:** March 08, 2010, 10:45:42 AM »

Quote from: witold on March 08, 2010, 10:18:28 AM

FREE FOR EVERYONE!!!

But then Dan won't have any money to continue the development, and then the development will stop. Isn't it better to pay for it?

witold · « **Reply #35 on:** March 08, 2010, 11:01:22 AM »

Only good option for me is a payment by SMS.

USD is too expensive for me.

1 USD=4 PLN

APODman · « **Reply #36 on:** March 09, 2010, 05:16:37 AM »

Quote from: Chaotic Cow on March 07, 2010, 08:16:23 PM

Quote from: deoxy99 on March 07, 2010, 07:35:22 PM
50 for Academic
25 for the others

That is what you meant to say.

This makes sense.

Less than Astrograv ?

I can agreed with the 25 for Academic / 50 for the others. Nothing less

[ ]Â´s

witold · « **Reply #37 on:** March 09, 2010, 07:15:26 AM »

5 PLN or less.

deoxy99 · « **Reply #38 on:** March 09, 2010, 08:07:07 AM »

The demand is high and the supply is low with that price. Think about supply and demand.

Bla · « **Reply #39 on:** March 09, 2010, 08:22:49 AM »

There is no supply I guess. People can just download the program on the website and activate it when they've entered the license.

deoxy99 · « **Reply #40 on:** March 09, 2010, 03:37:14 PM »

If the price is zero, the supply would be zero, and the demand would be infinite.

Dan Dixon · « **Reply #41 on:** March 09, 2010, 06:53:40 PM »

Quote from: Bla on March 03, 2010, 11:20:23 PM

It's a good question what it should cost. The more it costs, the less people will buy it.

Bla's got it. This is the key issue.

If it's priced at $10 we'd have to sell 4 times the number of copies to make the same amount of money if it was priced at $40. (considering the cost of bandwidth and payment transaction fees it might be more like 4.2-4.5 instead of 4)

We have decided that it will be a single price for everyone (individual uses and educational customers) and that there will be discounts for buying packs of 10 or more.

As a side note on costs:
Paypal & Google both take $0.30+3% so if someone buys for less than $0.30 we get nothing and a purchase for $1 results in ~ $0.65 income.

Chaotic Cow · « **Reply #42 on:** March 09, 2010, 07:04:48 PM »

This is why $20 fits.

It is right in the middle.

Dan Dixon · « **Reply #43 on:** March 09, 2010, 07:07:32 PM »

$10 and $40 were just examples.

And the middle of $10 and $40 is $25 = ((40-10)/2)+10

deoxy99 · « **Reply #44 on:** March 09, 2010, 07:15:07 PM »

25 dollars is fine.

mustacheman · « **Reply #45 on:** March 09, 2010, 07:55:04 PM »

Yeah, about 20-25 dollars should be good.

deoxy99 · « **Reply #46 on:** March 09, 2010, 08:07:39 PM »

How do you determine the middle of 20-25 dollars?

atomic7732 · « **Reply #47 on:** March 09, 2010, 08:10:03 PM »

22.50?

(a_b)/b

kind of

You take all your numbers you want to average and divide it by as many as you have

So a = numbers, n = amount of them

so,

(20+25)/2

There are 2 numbers, and they are 20 and 25.

20+25 = 45

45/2 is ... i guess 22.5

deoxy99 · « **Reply #48 on:** March 09, 2010, 08:10:41 PM »

Yes. My dad told me the answer.

deoxy99 · « **Reply #49 on:** March 09, 2010, 08:11:40 PM »

$22.50 is the middle of the set 20 - 25, which are the prices close to 25, which is the middle of the set 10 - 40.
$22.50 is the ideal price.

atomic7732 · « **Reply #50 on:** March 09, 2010, 08:13:37 PM »

My confirmed price I say is 30 dollars!

And a $55 dollar double set!

deoxy99 · « **Reply #51 on:** March 09, 2010, 08:14:54 PM »

The price is the average of yours and mine.
The average is: $26.25

deoxy99 · « **Reply #52 on:** March 09, 2010, 08:34:16 PM »

$26.25 would have an approximately equal demand.

atomic7732 · « **Reply #53 on:** March 09, 2010, 09:08:36 PM »

Yes, but nothing is always equal, if we go by the rules that twice the price less gives 1.5 more people and $30 gives 500 buyers, then we should be able to have a maximum of...

Well this will not work... Since... We cannot know the rate of people! It may be n^n.this would thus yeild...

No... I am not sure, but it may have to do with x to the xth root, e, i, phi, and/or pi! I assume e and i may be involved.

witold · « **Reply #54 on:** March 09, 2010, 10:25:09 PM »

US will cheaper

if we Dan will start commercials in web. Like facebook, Myspace etc.

deoxy99 · « **Reply #55 on:** March 09, 2010, 10:53:54 PM »

He could even advertise it on TV ads, when he has the money.

Dan Dixon · « **Reply #56 on:** March 10, 2010, 01:51:29 AM »

Quote from: NeutronStar on March 09, 2010, 08:10:03 PM

22.50

Right. For some reason I was doing it the hard way.

(20+25)/2 = 45/2 = 22.5
or
(25-20)/2 + 20 = 5/2 + 20 = 22.5

Chaotic Cow · « **Reply #57 on:** March 10, 2010, 05:35:13 AM »

Thanks Dan for outsmarting me. D: lol

JoelM935 · « **Reply #58 on:** March 14, 2010, 01:32:23 PM »

I think the price should be the original recommended price(25USD or 13.5GBP) - what you paid for Universe Sandbox 1. And if you paid $25 or Â£13.5 it should be around $10 or Â£5.

deoxy99 · « **Reply #59 on:** March 14, 2010, 01:42:01 PM »

Quote from: Dan Dixon on March 10, 2010, 01:51:29 AM

Quote from: NeutronStar on March 09, 2010, 08:10:03 PM
22.50

Right. For some reason I was doing it the hard way.

(20+25)/2 = 45/2 = 22.5
or
(25-20)/2 + 20 = 5/2 + 20 = 22.5

I didn't know it had to do with averaging.