Hi everyone,
I m doing a excel program to calculate the luminosity of a star with the Radius and the temperature in Kelvin of is surface....
I use the formula L = A X F
A is the Surface area of the sphere (lets supose its a perfect sphere...)
the radius i use is in Km
So A = 4лR2
F = σT4
σ = 5,67E-8
It give pretty huge numbers....do i need to devise it by something to get a realistic luminosity?
Ex: My star have a radius of: 540 000 Km and a surface temperature of: 3950
Our sun have a luminosity of : 3.84E26
My star have a luminosity of : 5,05788E19
So if i divide My star with the sun to have a 1 Ratio it equal: 1,31716E-7 Wich is ridiculously low....lol
But...it seem to be realistic when i multiply by (1,0E6) wich it give a final luminosity of 0,1317
It seem kinda realistic for a star of this size and temperature...
let me know what you think....i was having some free time lol