Welcome, Guest

Author Topic: Word game (maths somewhat)  (Read 1749 times)

Darvince

  • *****
  • Posts: 1842
  • 差不多
Word game (maths somewhat)
« on: November 12, 2011, 02:24:42 PM »
You have to take letters, and make it into something like this:
f(a+f)=af(f-g)
The next post then has to take out or add one, or change one letters.
ex:
f(a+i)=l
fa=l
ft=(l)
ft=(l+g)

atomic7732

  • Global Moderator
  • *****
  • Posts: 3849
  • caught in the river turning blue
    • Paladin of Storms
Re: Word game (maths somewhat)
« Reply #1 on: November 12, 2011, 02:44:52 PM »
equivalent formulae?

And I'm not sure I get it. Whatever

Since you're failing didn't give us anything to start with:

r - q(ba) = b - n(q + x)

Darvince

  • *****
  • Posts: 1842
  • 差不多
Re: Word game (maths somewhat)
« Reply #2 on: November 12, 2011, 02:58:44 PM »
r - ba = b - n(q + x)

atomic7732

  • Global Moderator
  • *****
  • Posts: 3849
  • caught in the river turning blue
    • Paladin of Storms
Re: Word game (maths somewhat)
« Reply #3 on: November 12, 2011, 03:04:05 PM »
That's not equivalent... How does this game work?

Darvince

  • *****
  • Posts: 1842
  • 差不多
Re: Word game (maths somewhat)
« Reply #4 on: November 12, 2011, 03:05:40 PM »
You add or subtract, or change one variable in teh equation...