Bong: the math is rather easy. Using radicals square root of both sides to get rid of the exponent. Reorder the 2 in abjds2f for my own ease of use since multiplication is commutative. Solving for af, so divide both sides by 2bjds. Reduce.
bjds can easily be wxyz, which are coordinates. This is in an integral (four of them). There's 4 integral coordinates, so it's a hypersphere (4 dimensional). AF is merely a placeholder for a Radius of the hypersphere (I hope. Otherwise, it's a 6dimensional object and that's outside of my immediate ability).
The image is an example of a hypersphere, I could get software to map the actual if you guys would prefer. Even then, as the example, it's a simplistic representation.
Darvince: As I just now made mention, it depends. If I don't substitute for wxyz, then I'd have to assume it's their actual coordinate values. Making it 26th+ dimensional (as there is an A). Which would be some kind of weird inverted 26-dimensional monster of a shape. I tried doing the math but all I got was:
So for the time being, I'll stick with my assumption. It's easier to imagine n+4 shapes. Here's an example of a Reimann sphere in n+6:
Topic: Math skillz (Read 3447 times)
