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atomic7732

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I challenge you!
« on: December 17, 2011, 05:15:58 PM »
I challenge you to find me a number that is divisible by 12, but not by 2.

FiahOwl

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Re: I challenge you!
« Reply #1 on: December 17, 2011, 05:19:48 PM »

This message is only viewable with Universe Sandbox Galaxy Edition. Access it and much more with promo-code '49648'.

« Last Edit: March 22, 2021, 12:57:11 AM by FiahOwl »

deoxy99

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Re: I challenge you!
« Reply #2 on: December 17, 2011, 05:24:08 PM »
PWNED!

atomic7732

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Re: I challenge you!
« Reply #3 on: December 17, 2011, 05:29:49 PM »
That's the point...

Now go to 90N and travel west.

smjjames

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Re: I challenge you!
« Reply #4 on: December 17, 2011, 05:35:50 PM »
Go in a circle clockwise around 90N, or spin in place clockwise :)

deoxy99

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Re: I challenge you!
« Reply #5 on: December 17, 2011, 05:36:34 PM »
You can't, as 90N is a single point. Or you can keep spinning around the point.

Damn it, ninja'd by smjjames.

atomic7732

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Re: I challenge you!
« Reply #6 on: December 17, 2011, 05:37:14 PM »
And now divide by zero.

smjjames

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Re: I challenge you!
« Reply #7 on: December 17, 2011, 05:39:03 PM »
And now divide by zero.

ERROR! DOES NOT COMPUTE! *CRASH!*

Thats the funny answer, the real answer is anything divided by zero is zero, or infinity.

Bla

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Re: I challenge you!
« Reply #8 on: December 17, 2011, 05:39:13 PM »

deoxy99

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Re: I challenge you!
« Reply #9 on: December 17, 2011, 05:39:57 PM »
It's infinity, ninja'd again by both Bla and smjjames.

atomic7732

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Re: I challenge you!
« Reply #10 on: December 17, 2011, 05:48:11 PM »
My math teacher says the people who say it's infinity are wrong. :-\

smjjames

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Re: I challenge you!
« Reply #11 on: December 17, 2011, 05:49:50 PM »
Infinitely zero then.

deoxy99

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Re: I challenge you!
« Reply #12 on: December 17, 2011, 05:53:43 PM »
Good, so I didn't get ninja'd:

COMPLEX INFINITY FTW!

smjjames

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Re: I challenge you!
« Reply #13 on: December 17, 2011, 05:55:18 PM »
Never heard of the term complex infinity before, and it's still infinity anyway.

deoxy99

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Re: I challenge you!
« Reply #14 on: December 17, 2011, 05:58:48 PM »
Complex Infinity is, according to WolframAlpha:
The complex quantity with infinite magnitude but indeterminate phase.

Try this link with epic algebra to prove the answer is complex infinity no matter what number you divide by zero (except 0/0 which breaks the laws of algebra): http://www.wolframalpha.com/input/?i=x+divided+by+zero
« Last Edit: December 17, 2011, 06:02:56 PM by deoxy99 »

vh

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Re: I challenge you!
« Reply #15 on: December 17, 2011, 06:16:44 PM »
add 1 to 1 and get 3
HNNNNG

atomic7732

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Re: I challenge you!
« Reply #16 on: December 17, 2011, 06:22:50 PM »
nothing divided in no parts should be zero. Just like nothing divided in many parts.

deoxy99

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Re: I challenge you!
« Reply #17 on: December 17, 2011, 06:29:16 PM »
0 divided by 0 is indeterminate, same with 0 divided by anything other than 0. There, your answer, you impossible to please person.

atomic7732

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Re: I challenge you!
« Reply #18 on: December 17, 2011, 07:29:11 PM »
Ummm no... 0/8 is 0. It's mathematically proven...

smjjames

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Re: I challenge you!
« Reply #19 on: December 17, 2011, 07:38:26 PM »
I already said zero, so there, and lets move on Neu.......

atomic7732

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Re: I challenge you!
« Reply #20 on: December 17, 2011, 07:51:44 PM »
That was my last challenge.

Bla

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Re: I challenge you!
« Reply #21 on: December 18, 2011, 03:03:37 AM »
In math we started on infinitesimal calculus this year, and there we often divide by zero, which gives infinity. And similarly dividing by infinity gives 0.

According to Wikipedia, you can't do it normally, but only in infinitesimal calculus.
http://en.wikipedia.org/wiki/Division_by_0

Which makes no sense to me logically. Maybe because you just don't want infinites normally.
But logically a number divided by 0 should give infinity, as the smaller the number you divide it by, the greater the number becomes.

Our teacher wrote this example on the blackboard. Dividing by negative zero becomes negative infinity, dividing by zero becomes positive infinity. Kol.

Ask your teacher about infinitesimal calculus.

vh

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Re: I challenge you!
« Reply #22 on: December 19, 2011, 01:52:57 PM »
lol whats an asympopter or whatever and its all in danish
*eyes*

Bla

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Re: I challenge you!
« Reply #23 on: December 19, 2011, 02:13:47 PM »
lol whats an asympopter or whatever and its all in danish
*eyes*
Asymptoter is plural.
It means asymptotes.