Welcome,
Guest
Login
or
Register
Buy Universe Sandbox
Requires Windows, Mac, or Linux
Home
Help
Search
Login
Register
Universe Sandbox
»
General Category
»
Everything Else
»
Word game (maths somewhat)
« previous
next »
Print
Pages: [
1
]
Author
Topic: Word game (maths somewhat) (Read 1746 times)
Darvince
Posts: 1842
差不多
Word game (maths somewhat)
«
on:
November 12, 2011, 02:24:42 PM »
You have to take letters, and make it into something like this:
f(a+f)=af(f-g)
The next post then has to take out or add one, or change one letters.
ex:
f(a+i)=l
fa=l
ft=(l)
ft=(l+g)
Logged
atomic7732
Global Moderator
Posts: 3849
caught in the river turning blue
Re: Word game (maths somewhat)
«
Reply #1 on:
November 12, 2011, 02:44:52 PM »
equivalent formulae?
And I'm not sure I get it. Whatever
Since you
're failing
didn't give us anything to start with:
r - q(ba) = b - n(q + x)
Logged
Darvince
Posts: 1842
差不多
Re: Word game (maths somewhat)
«
Reply #2 on:
November 12, 2011, 02:58:44 PM »
r - ba = b - n(q + x)
Logged
atomic7732
Global Moderator
Posts: 3849
caught in the river turning blue
Re: Word game (maths somewhat)
«
Reply #3 on:
November 12, 2011, 03:04:05 PM »
That's not equivalent... How does this game work?
Logged
Darvince
Posts: 1842
差不多
Re: Word game (maths somewhat)
«
Reply #4 on:
November 12, 2011, 03:05:40 PM »
You add or subtract, or change one variable in teh equation...
Logged
Print
Pages: [
1
]
« previous
next »
Universe Sandbox
»
General Category
»
Everything Else
»
Word game (maths somewhat)